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emergency medical supply
What is the horizontal distance..?
A helicopter is flying horizontally at 7.7 m/s and an altitude of 17 m when a package of emergency medical supplies is ejected horizontally backward with a speed of 10 m/s relative to the helicopter. Ignoring air resistance, what is the horizontal distance between the package and the helicopter when the package hits the ground?
THANKS!
we assume the force the chopper is applying is constant. But the drag is not constant, it increases with the square of velocity. Therefore the resultant force (Fres = F - Fd - other frictions) is not constant ... and neither is acceleration (a = Fres/m).
The trick to this problem is to recognize that the final velocity is reached when there is equilibrium between the force the chopper applies (Fnet) and the drag (Fd). At that velocity, there is no resultant force to give further acceleration .
So at that equilibrium point, Fnet = F - other frictions = Fd = -0.5(pv^2)ACd. Since the formula is a function of velocity, all you need to do is solve F - other frictions = -0.5(pv^2)ACd for v^2 and take the square root.
I hope that helps,
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